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Example – 1 . Marks out of 50 obtained by 100 students are given in the following data :

Marks obtained 20 29 28 33 42 38 43 25
No. of students 6 28 24 15 2 4 1 20

Solution :- 

Marks obtained Number of students (Frequency)
20
25
28
29
33
38
42
43

6
20
24
28
15
4
2
1

Total

100

Here n = 100, which is even. Therefore, the median will be the average of  50th and 51th observations. We proceed as follows :

Marks obtained

Number of students

Cumulative frequency

20

6

6

25

20

26

28

24

50

29

28

78

33

15

93

38

4

97

42

2

99

43

1

100

From the above table, we se that : 50th observation = 28

and    51th observation = 29

So,     Median = ½(28 + 29) = 28.5

Median of a grouped data :-

 

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Maths by Mr. M. P. Keshari

 

Chapter - 24   Chapter - 25   Chapter - 26
  Chapter - 27   Chapter - 28   Chapter - 29

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