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ICSE Guess > ICSE/ISC eBooks > Class X > Maths by Mr. M. P. Keshari

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Chapter - 17

Loci

Locus : - Locus is a path traces out by a moving point satisfying certain given geometrical conditions.

Theorem – I

The locus of a point equidistant from the two fixed points is the perpendicular bisector of the line joining the fixed point.

Part – I

Every point which is equidistant from two fixed points A and B lies on the perpendicular bisector of AB.

Given : - A and B are two fixed point and a point P such that PA = PB.

To Prove : - P Lies on the perpendicular bisector of AB.

Construction : - A and B is joined. AB is bisected at M. PA, PB and PM are joined.

Proof : -

1.

  1. PA = PB
  2. AM = BM
  3. PM = PM

1.

  1. Given
  2. By construction
  3. Common
2. 2. S.S.S
3. 3. Statement (2)
4. 4. AMB is a straight line
5. = 900 5. Statements (3), (4)
6. i.e. Plies on the perpendicular bisector of AB. 6. Statement (5)

Part – II Conversely, every point on the perpendicular bisector of AB is equidistant from A and B.

Given: - Two given points A and B. P is any point on the perpendicular bisector ‘l’ of AB.

To Prove: - PA = PB

Proof: -

Statement

Reason

1.

  1. AM = BM
  2. PM = PM

 1.

  1. M lies on bisector of AB
  2. Each being 900
  3. Common

2.

2. S.A.S

3. PA = PB

3. Statement (2)

Hence every point equidistant from A and B lies on the perpendicular bisector of AB and every point on the perpendicular bisector of AB is equidistance from A and B.

 

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Maths by Mr. M. P. Keshari

 

Chapter - 12   Chapter - 13   Chapter - 14
  Chapter - 15   Chapter - 16   Chapter - 17
  Chapter - 18   Chapter - 19   Chapter - 20
  Chapter - 21   Chapter - 22   Chapter - 23

 


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